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56.合并区间

1. 按左区间由小到大排序

时间复杂度需要排序O(nlogn),空间复杂度存答案O(n)

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class Solution {
public:
// static bool cmp(const vector<int>& a, const vector<int>& b) {
// if (a[0] < b[0])
// return true;
// else
// return false;
// }

vector<vector<int>> merge(vector<vector<int>>& intervals) {
int n = intervals.size();
if (n <= 1)
return intervals;
// sort(intervals.begin(), intervals.end(), cmp);
sort(intervals.begin(), intervals.end()); // vector有比较操作符

vector<vector<int> > ans;
vector<int> cur(intervals[0]);
int left = cur[0], right = cur[1];
for (int i = 1; i < n; i++) {
if (intervals[i][0] <= right)
right = right >= intervals[i][1] ? right : intervals[i][1];
else {
ans.push_back({left, right});
left = intervals[i][0];
right = intervals[i][1];
}
}
ans.push_back({left, right});

return ans;
}
};